Math Problem Statement

form following table find the value of e^-1.17 using Grayss forward formula in answers

Solution

To find the value of e1.17e^{-1.17} using Gregory-Newton Forward Interpolation Formula, we need a table of function values at certain points. The Gregory-Newton Forward formula is generally used for evenly spaced data points. Here's the formula:

f(x)=f(x0)+uΔf(x0)+u(u1)2!Δ2f(x0)+u(u1)(u2)3!Δ3f(x0)+f(x) = f(x_0) + u\Delta f(x_0) + \frac{u(u-1)}{2!}\Delta^2 f(x_0) + \frac{u(u-1)(u-2)}{3!}\Delta^3 f(x_0) + \ldots

where:

  • u=xx0hu = \frac{x - x_0}{h}
  • hh is the step size between the data points
  • Δf(x0),Δ2f(x0),\Delta f(x_0), \Delta^2 f(x_0), etc., are forward differences.

To proceed with finding e1.17e^{-1.17}, please provide the table of values (e.g., values of xx and corresponding function values f(x)f(x)), or let me know if you need help creating one.

Would you like me to guide you through the process step-by-step if you provide the necessary data?

Related Questions

  1. How do you calculate forward differences for interpolation?
  2. What is the significance of the Gregory-Newton Forward Interpolation Formula?
  3. How do you determine the step size hh in interpolation problems?
  4. What are the applications of interpolation formulas in real-life scenarios?
  5. Can backward interpolation be used similarly, and how does it differ?

Tip: Always ensure that the data points are evenly spaced when applying the Gregory-Newton Forward Interpolation Formula for accurate results.

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Math Problem Analysis

Mathematical Concepts

Numerical Methods
Interpolation
Exponential Functions

Formulas

Gregory-Newton Forward Interpolation Formula
f(x) = f(x_0) + uΔf(x_0) + (u(u-1)/2!)Δ^2f(x_0) + (u(u-1)(u-2)/3!)Δ^3f(x_0) + ...
u = (x - x_0) / h

Theorems

Gregory-Newton Forward Interpolation Theorem

Suitable Grade Level

Undergraduate (Numerical Methods / Applied Mathematics)